What is the d/(dm)(5m^2+15m^3) ?

The d/(dm)(5m^2+15m^3) is 10m+45m^2

What is the first d/(dm)(5m^2+15m^3) ?

The first d/(dm)(5m^2+15m^3) is 10m+45m^2

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\frac{d}{d m} (5 m^{2} + 15 m^{3})

10 m + 45 m^{2}

Solution steps

\frac{d}{d m} (5 m^{2} + 15 m^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d m} (5 m^{2}) + \frac{d}{d m} (15 m^{3})

\frac{d}{d m} (5 m^{2}) = 10 m

\frac{d}{d m} (15 m^{3}) = 45 m^{2}

= 10 m + 45 m^{2}

\int \frac{1}{9 e ^{- 5 x} + e ^{5 x}} d x

d er i v a t i v e y = 1 1^{t a n (6 x)}

\frac{d}{d x} (tan (x) - cot (x))

\int \frac{4}{sin ^{2} ( x )} d x

\frac{d}{d x} (sin (n arcsin (x)))

What is the d/(dm)(5m^2+15m^3) ?
The d/(dm)(5m^2+15m^3) is 10m+45m^2
What is the first d/(dm)(5m^2+15m^3) ?
The first d/(dm)(5m^2+15m^3) is 10m+45m^2