What is the derivative of e^{x^2-4}+4x+11 ?

The derivative of e^{x^2-4}+4x+11 is 2e^{x^2-4}x+4

What is the first derivative of e^{x^2-4}+4x+11 ?

The first derivative of e^{x^2-4}+4x+11 is 2e^{x^2-4}x+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (e^{x^{2} - 4} + 4 x + 11)

2 e^{x^{2} - 4} x + 4

Solution steps

\frac{d}{d x} (e^{x^{2} - 4} + 4 x + 11)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x^{2} - 4}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (11)

\frac{d}{d x} (e^{x^{2} - 4}) = e^{x^{2} - 4} \cdot 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (11) = 0

= e^{x^{2} - 4} \cdot 2 x + 4 + 0

Simplify

= 2 e^{x^{2} - 4} x + 4

\int (ln (7 x))^{2} d x

\int_{0}^{x^{2}} e^{t^{2}} d t

x \to \infty lim (- 2 x - 1)

\int 22 sec^{4} (θ) tan^{2} (θ) d θ

s l o p e (4.1) (1.1)

What is the derivative of e^{x^2-4}+4x+11 ?
The derivative of e^{x^2-4}+4x+11 is 2e^{x^2-4}x+4
What is the first derivative of e^{x^2-4}+4x+11 ?
The first derivative of e^{x^2-4}+4x+11 is 2e^{x^2-4}x+4