What is the solution for e^{x-y}dx+e^{y-x}dy=0 ?

The solution for e^{x-y}dx+e^{y-x}dy=0 is y=(ln(-e^{2x}+c_{1}))/2

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e^{x-y}dx+e^{y-x}dy=0

e^{x - y} d x + e^{y - x} d y = 0

y = \frac{ln ( - e ^{2 x} + c _{1} )}{2}

Solution steps

e^{x - y} d x + e^{y - x} d y = 0

Solve separable ODE:

y = \frac{ln ( - e ^{2 x} + c _{1} )}{2}

y = \frac{ln ( - e ^{2 x} + c _{1} )}{2}

d er i v a t i v e f (x^{2})

\frac{\partial}{\partial x} (\frac{1}{e ^{x}})

9 x - 4 y x^{2} + 1 \frac{d y}{d x} = 0

\frac{d}{d x} (4 sin^{3} (5 x))

t an g e n t \frac{6}{( 4 x + 1 )}

What is the solution for e^{x-y}dx+e^{y-x}dy=0 ?
The solution for e^{x-y}dx+e^{y-x}dy=0 is y=(ln(-e^{2x}+c_{1}))/2