What is (\partial)/(\partial x)(sin(pi(6x-5y))) ?

The answer to (\partial)/(\partial x)(sin(pi(6x-5y))) is cos(pi(6x-5y))*6pi

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(\partial)/(\partial x)(sin(pi(6x-5y)))

\frac{\partial}{\partial x} (sin (π (6 x - 5 y)))

cos (π (6 x - 5 y)) \cdot 6 π

Solution steps

\frac{\partial}{\partial x} (sin (π (6 x - 5 y)))

Treat

y

as a constant

Apply the chain rule:

cos (π (6 x - 5 y)) \frac{\partial}{\partial x} (π (6 x - 5 y))

= cos (π (6 x - 5 y)) \frac{\partial}{\partial x} (π (6 x - 5 y))

\frac{\partial}{\partial x} (π (6 x - 5 y)) = 6 π

= cos (π (6 x - 5 y)) \cdot 6 π

d er i v a t i v e f (x) = \frac{3}{( x ^{2} - 5 x ) ^{2}}

d er i v a t i v e y = 1 cos (2) (x)

t a y l or e^{t^{2}}

\int e^{x} sec^{2} (e^{x}) d x

y^{^{''}} + 25 y = 20 sin (5 x)

What is (\partial)/(\partial x)(sin(pi(6x-5y))) ?
The answer to (\partial)/(\partial x)(sin(pi(6x-5y))) is cos(pi(6x-5y))*6pi