What is laplacetransform sin(2(t-pi/2)) ?

The answer to laplacetransform sin(2(t-pi/2)) is -2/(s^2+4)

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laplacetransform sin(2(t-pi/2))

laplace transform

sin (2 (t - \frac{π}{2}))

- \frac{2}{s ^{2} + 4}

Solution steps

L {sin (2 (t - \frac{π}{2}))}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (2 (t - \frac{π}{2}))} = \frac{s sin ( - π ) + 2 cos ( - π )}{s ^{2} + 2 ^{2}}

= \frac{s sin ( - π ) + 2 cos ( - π )}{s ^{2} + 2 ^{2}}

= - \frac{2}{s ^{2} + 4}

a re a x^{2} - 4 x, x - 4

\int sin (9 π x) d x

\frac{d}{d x} (\frac{3 x ^{4} + 7}{x ^{2}})

\int 2 x (x^{2} + 6)^{6} d x

R \to 1 + lim (\frac{1}{R - 1})

What is laplacetransform sin(2(t-pi/2)) ?
The answer to laplacetransform sin(2(t-pi/2)) is -2/(s^2+4)