What is laplacetransform 9/4 t^2e^{2t}e^{3t} ?

The answer to laplacetransform 9/4 t^2e^{2t}e^{3t} is 9/(2(s-5)^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

laplacetransform 9/4 t^2e^{2t}e^{3t}

laplace transform

\frac{9}{4} t^{2} e^{2 t} e^{3 t}

\frac{9}{2 ( s - 5 ) ^{3}}

Solution steps

L {\frac{9}{4} e^{2 t} e^{3 t} t^{2}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= \frac{9}{4} L {t^{2} e^{2 t} e^{3 t}}

L {t^{2} e^{2 t} e^{3 t}} : \frac{2}{( s - 5 ) ^{3}}

= \frac{9}{4} \cdot \frac{2}{( s - 5 ) ^{3}}

Refine

\frac{9}{4} \frac{2}{( s - 5 ) ^{3}} : \frac{9}{2 ( s - 5 ) ^{3}}

= \frac{9}{2 ( s - 5 ) ^{3}}

\frac{d}{d x} (x tan (2 x) + 7)

\int - \frac{1}{64} e^{- 4 x} d x

y^{^{'}} = e^{2 y} sin (3 x)

t a y l or sin (x), \frac{π}{4}

y^{^{''}} + 6 y^{^{'}} + 8 y = 4 sin (2 t)

What is laplacetransform 9/4 t^2e^{2t}e^{3t} ?
The answer to laplacetransform 9/4 t^2e^{2t}e^{3t} is 9/(2(s-5)^3)