What is (\partial)/(\partial u)(2u+v) ?

The answer to (\partial)/(\partial u)(2u+v) is 2

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(\partial)/(\partial u)(2u+v)

\frac{\partial}{\partial u} (2 u + v)

2

Solution steps

\frac{\partial}{\partial u} (2 u + v)

Treat

v

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial u} (2 u) + \frac{\partial}{\partial u} (v)

\frac{\partial}{\partial u} (2 u) = 2

\frac{\partial}{\partial u} (v) = 0

= 2 + 0

Simplify

= 2

\int 5 x^{3} 3 (2 x^{4} - 4)^{2} d x

x \to 0 lim (\frac{cos ( x )}{96})

\frac{d y}{d t} + 0.3 t y = 9 t

l a pl a ce t r an s f or m 6 t - 3

l a pl a ce t r an s f or m t^{2} + e^{- 2 t} sin (3 t)

What is (\partial)/(\partial u)(2u+v) ?
The answer to (\partial)/(\partial u)(2u+v) is 2