What is the solution for (d^2y)/(dt^2)+9y=cos(2t) ?

The solution for (d^2y)/(dt^2)+9y=cos(2t) is y=c_{1}cos(3t)+c_{2}sin(3t)+1/5 cos(2t)

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(d^2y)/(dt^2)+9y=cos(2t)

\frac{d ^{2} y}{d t ^{2}} + 9 y = cos (2 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{1}{5} cos (2 t)

Solution steps

\frac{d ^{2} y}{d t ^{2}} + 9 y = cos (2 t)

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{1}{5} cos (2 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{1}{5} cos (2 t)

\int 2 x - 7 d x

\frac{d}{d θ} (- sin (θ))

s l o p e in t erce pt (6, - 6), (8, 8)

\frac{d}{d x} (9 ln (4 x))

\frac{d}{d x} (e^{x^{y}})

What is the solution for (d^2y)/(dt^2)+9y=cos(2t) ?
The solution for (d^2y)/(dt^2)+9y=cos(2t) is y=c_{1}cos(3t)+c_{2}sin(3t)+1/5 cos(2t)