What is the integral of e^{8x+7} ?

The integral of e^{8x+7} is 1/8 e^{8x+7}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of e^{8x+7}

\int e^{8 x + 7} d x

\frac{1}{8} e^{8 x + 7} + C

Solution steps

\int e^{8 x + 7} d x

Apply u-substitution

= \int e^{u} \frac{1}{8} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{8} e^{u}

Substitute back

u = 8 x + 7

= \frac{1}{8} e^{8 x + 7}

Add a constant to the solution

= \frac{1}{8} e^{8 x + 7} + C

\frac{d}{d x} (\frac{4 x ^{3} + 9}{x})

\frac{d}{d t} (sin (ω t + θ))

x e^{x} y^{^{'}} + 2 e^{x} y = 0

\int 9 - 16 x^{2} d x

\int (\frac{1}{x ^{2} - 9}) d x