What is the integral of 3^{t^2} ?

The integral of 3^{t^2} is (sqrt(pi)\erfi(tsqrt(ln(3))))/(2sqrt(ln(3)))+C

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integral of 3^{t^2}

\int 3^{t^{2}} d t

\frac{π erfi ( t ln ( 3 ) )}{2 ln ( 3 )} + C

Solution steps

\int 3^{t^{2}} d t

Use the nonelementary integral:

\int 3^{t^{2}} d t = \frac{π erfi ( t ln ( 3 ) )}{2 ln ( 3 )}

= \frac{π erfi ( t ln ( 3 ) )}{2 ln ( 3 )}

Add a constant to the solution

= \frac{π erfi ( t ln ( 3 ) )}{2 ln ( 3 )} + C

\frac{d}{d x} (\frac{3 + 2 x}{x})

\frac{d ^{3}}{d x ^{3}} (6 t + 3)

x^{2} d x + 3 y (x - 1) d y = 0

\int sin (x) + 5 d x

\int \frac{ln ( x )}{16} d x

What is the integral of 3^{t^2} ?
The integral of 3^{t^2} is (sqrt(pi)\erfi(tsqrt(ln(3))))/(2sqrt(ln(3)))+C