What is the integral of 1/((3-2x)^2) ?

The integral of 1/((3-2x)^2) is 1/(2(3-2x))+C

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integral of 1/((3-2x)^2)

\int \frac{1}{( 3 - 2 x ) ^{2}} d x

\frac{1}{2 ( 3 - 2 x )} + C

Solution steps

\int \frac{1}{( 3 - 2 x ) ^{2}} d x

Apply u-substitution

= \int - \frac{1}{2 u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

= - \frac{1}{2} (- \frac{1}{u})

Substitute back

u = 3 - 2 x

= - \frac{1}{2} (- \frac{1}{3 - 2 x})

Simplify

- \frac{1}{2} (- \frac{1}{3 - 2 x}) : \frac{1}{2 ( 3 - 2 x )}

= \frac{1}{2 ( 3 - 2 x )}

Add a constant to the solution

= \frac{1}{2 ( 3 - 2 x )} + C

What is the integral of 1/((3-2x)^2) ?
The integral of 1/((3-2x)^2) is 1/(2(3-2x))+C