derivative of 6+3x-4x(7x+1^2)

Lösung

\frac{d}{d x} (6 + 3 x - 4 x (7 x + 1)^{2})

- 588 x^{2} - 112 x - 1

Schritte zur Lösung

\frac{d}{d x} (6 + 3 x - 4 x (7 x + 1)^{2})

Vereinfache

6 + 3 x - 4 x (7 x + 1)^{2} : - 196 x^{3} - 56 x^{2} - x + 6

= \frac{d}{d x} (- 196 x^{3} - 56 x^{2} - x + 6)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (196 x^{3}) - \frac{d}{d x} (56 x^{2}) - \frac{d x}{d x} + \frac{d}{d x} (6)

\frac{d}{d x} (196 x^{3}) = 588 x^{2}

\frac{d}{d x} (56 x^{2}) = 112 x

\frac{d x}{d x} = 1

\frac{d}{d x} (6) = 0

= - 588 x^{2} - 112 x - 1 + 0

Vereinfache

= - 588 x^{2} - 112 x - 1

\int 13 ln (3 x) d x

\frac{\partial}{\partial x} (2 x y ln (x))

\frac{\partial}{\partial t} (sin (2 x) cos (2 t))

\frac{d}{d x} (\frac{8 x}{7 - tan ( x )})

l o n g d i v i s i o n \frac{2 x + 3}{3 x - 2}