What is the derivative of 20x^2+(180/x) ?

The derivative of 20x^2+(180/x) is 40x-(180)/(x^2)

What is the first derivative of 20x^2+(180/x) ?

The first derivative of 20x^2+(180/x) is 40x-(180)/(x^2)

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\frac{d}{d x} (20 x^{2} + \frac{180}{x})

40 x - \frac{180}{x ^{2}}

Solution steps

\frac{d}{d x} (20 x^{2} + \frac{180}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (20 x^{2}) + \frac{d}{d x} (\frac{180}{x})

\frac{d}{d x} (20 x^{2}) = 40 x

\frac{d}{d x} (\frac{180}{x}) = - \frac{180}{x ^{2}}

= 40 x - \frac{180}{x ^{2}}

What is the derivative of 20x^2+(180/x) ?
The derivative of 20x^2+(180/x) is 40x-(180)/(x^2)
What is the first derivative of 20x^2+(180/x) ?
The first derivative of 20x^2+(180/x) is 40x-(180)/(x^2)