What is the derivative of 12-3x-4y ?

The derivative of 12-3x-4y is -4(dy)/(dx)-3

What is the first derivative of 12-3x-4y ?

The first derivative of 12-3x-4y is -4(dy)/(dx)-3

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\frac{d}{d x} (12 - 3 x - 4 y)

- 4 \frac{d y}{d x} - 3

Solution steps

\frac{d}{d x} (12 - 3 x - 4 y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (12) - \frac{d}{d x} (3 x) - \frac{d}{d x} (4 y)

\frac{d}{d x} (12) = 0

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4 y) = 4 \frac{d y}{d x}

= 0 - 3 - 4 \frac{d y}{d x}

Simplify

= - 4 \frac{d y}{d x} - 3

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What is the derivative of 12-3x-4y ?
The derivative of 12-3x-4y is -4(dy)/(dx)-3
What is the first derivative of 12-3x-4y ?
The first derivative of 12-3x-4y is -4(dy)/(dx)-3