What is the tangent of f(x)= 3/(5x+2),\at x=-1 ?

The tangent of f(x)= 3/(5x+2),\at x=-1 is y=-5/3 x-8/3

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tangent of f(x)= 3/(5x+2),\at x=-1

tangent of

f (x) = \frac{3}{5 x + 2}, at x = - 1

y = - \frac{5}{3} x - \frac{8}{3}

Solution steps

Find the tangent point:

(- 1, - 1)

Find the slope of

f (x) = \frac{3}{5 x + 2} : \frac{df ( x )}{d x} = - \frac{15}{( 5 x + 2 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{5}{3}

Find the line with slope m=

- \frac{5}{3}

and passing through

(- 1, - 1) : y = - \frac{5}{3} x - \frac{8}{3}

y = - \frac{5}{3} x - \frac{8}{3}

\int (2 x + 1)^{\frac{5}{6}} d x

\frac{\partial}{\partial x} (32 x + 13 y + 90)

\frac{d}{d t} (ln (a + v (t) t))

\frac{d}{d x} ((- 1)^{n} x^{2 n})

y^{^{'}} = 0.5 y, y (2) = 100

What is the tangent of f(x)= 3/(5x+2),\at x=-1 ?
The tangent of f(x)= 3/(5x+2),\at x=-1 is y=-5/3 x-8/3