What is the derivative of y=ln(9x) ?

The derivative of y=ln(9x) is 1/x

What is the first derivative of y=ln(9x) ?

The first derivative of y=ln(9x) is 1/x

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derivative of

y = ln (9 x)

\frac{1}{x}

Solution steps

\frac{d}{d x} (ln (9 x))

Apply the chain rule:

\frac{1}{9 x} \frac{d}{d x} (9 x)

= \frac{1}{9 x} \frac{d}{d x} (9 x)

\frac{d}{d x} (9 x) = 9

= \frac{1}{9 x} \cdot 9

Simplify

\frac{1}{9 x} \cdot 9 : \frac{1}{x}

= \frac{1}{x}

x \to \infty lim (m x + b)

\int \frac{1}{( x ^{2} - 8 x ) ^{\frac{3}{2}}} d x

\frac{\partial}{\partial x} (\frac{( 5 x + 3 )}{y - 2})

\int 20

\frac{d}{d x} (sin (x + 3))

What is the derivative of y=ln(9x) ?
The derivative of y=ln(9x) is 1/x
What is the first derivative of y=ln(9x) ?
The first derivative of y=ln(9x) is 1/x