What is the solution for 2x(dy)/(dx)-8y=x^{-8} ?

The solution for 2x(dy)/(dx)-8y=x^{-8} is y=-1/(24x^8)+c_{1}x^4

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2x(dy)/(dx)-8y=x^{-8}

2 x \frac{d y}{d x} - 8 y = x^{- 8}

y = - \frac{1}{24 x ^{8}} + c_{1} x^{4}

Solution steps

2 x \frac{d y}{d x} - 8 y = x^{- 8}

Solve linear ODE:

y = - \frac{1}{24 x ^{8}} + c_{1} x^{4}

y = - \frac{1}{24 x ^{8}} + c_{1} x^{4}

\frac{2}{x}, \frac{1}{2} x, 1, 2

\frac{d}{d x} (ln (\frac{2 x - 1}{x - 1}))

\frac{d}{d u} (2 u)

f (x) = x^{2} - 1, x = - 1, x = 1

sec^{2} (7 x)

What is the solution for 2x(dy)/(dx)-8y=x^{-8} ?
The solution for 2x(dy)/(dx)-8y=x^{-8} is y=-1/(24x^8)+c_{1}x^4