What is the derivative of 2(sin(x^2+2x^2cos(x^2))) ?

The derivative of 2(sin(x^2+2x^2cos(x^2))) is 2(6xcos(x^2)-4x^3sin(x^2))

What is the first derivative of 2(sin(x^2+2x^2cos(x^2))) ?

The first derivative of 2(sin(x^2+2x^2cos(x^2))) is 2(6xcos(x^2)-4x^3sin(x^2))

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\frac{d}{d x} (2 (sin (x^{2}) + 2 x^{2} cos (x^{2})))

2 (6 x cos (x^{2}) - 4 x^{3} sin (x^{2}))

Solution steps

\frac{d}{d x} (2 (sin (x^{2}) + 2 x^{2} cos (x^{2})))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin (x^{2}) + 2 x^{2} cos (x^{2}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 2 (\frac{d}{d x} (sin (x^{2})) + \frac{d}{d x} (2 x^{2} cos (x^{2})))

\frac{d}{d x} (sin (x^{2})) = cos (x^{2}) \cdot 2 x

\frac{d}{d x} (2 x^{2} cos (x^{2})) = 2 (2 x cos (x^{2}) - 2 x^{3} sin (x^{2}))

= 2 (cos (x^{2}) \cdot 2 x + 2 (2 x cos (x^{2}) - 2 x^{3} sin (x^{2})))

Expand

cos (x^{2}) \cdot 2 x + 2 (2 x cos (x^{2}) - 2 x^{3} sin (x^{2})) : 6 x cos (x^{2}) - 4 x^{3} sin (x^{2})

= 2 (6 x cos (x^{2}) - 4 x^{3} sin (x^{2}))

\int \frac{6 x}{5 ( x ^{2} + 7 ) ^{2}} d x

\frac{d}{d x} ((x^{10} - 1)^{3})

\frac{\partial}{\partial x} (y^{2})

\int x os (8 x^{2} + π) d x

\frac{d}{d x} ((x^{2} + 4 x + 6)^{5})

What is the derivative of 2(sin(x^2+2x^2cos(x^2))) ?
The derivative of 2(sin(x^2+2x^2cos(x^2))) is 2(6xcos(x^2)-4x^3sin(x^2))
What is the first derivative of 2(sin(x^2+2x^2cos(x^2))) ?
The first derivative of 2(sin(x^2+2x^2cos(x^2))) is 2(6xcos(x^2)-4x^3sin(x^2))