limit as x approaches infinity of cos(0)

解答

x \to \infty lim (cos (0))

1

求解步骤

x \to \infty lim (cos (0))

x \to a lim c = c

= cos (0)

使用以下普通恒等式:

cos (0) = 1

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

d er i v a t i v e sin (x) + \frac{5}{8} cot (x)

x \to - 6 lim (x^{2} - 1)

n = 1 \sum \infty \frac{1}{e ^{2 n}}

(12 - 20 y + e^{- 5 x}) d x - 4 d y = 0

\int 8 x^{\frac{1}{3}} + 8 x^{- \frac{1}{3}} d x