-10x^2y+y^'=9x^2

Lösung

- 10 x^{2} y + y^{^{'}} = 9 x^{2}

y = \frac{e ^{\frac{10 x ^{3} + c _{1}}{3}}}{10} - \frac{9}{10}

Schritte zur Lösung

- 10 x^{2} y + y^{'} (x) = 9 x^{2}

Solve separable ODE:

y = \frac{e ^{\frac{10 x ^{3} + c _{1}}{3}}}{10} - \frac{9}{10}

y = \frac{e ^{\frac{10 x ^{3} + c _{1}}{3}}}{10} - \frac{9}{10}

\int \frac{1}{3 ^{x} + 1} d x

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y (0) = - 3, y^{^{'}} (0) = 5

\int_{1}^{3} (x + 2) (x - 1)^{5} d x

\frac{d}{d x} (\frac{- x ^{2} - 4 x - 1}{4 x - 3})

\int e^{x^{3} + 1} x^{2} d x