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Popular Calculus >

(y^'+y^2)/(x^2)=0

Solution

\frac{y ^{^{'}} + y ^{2}}{x ^{2}} = 0

Solution

y = - \frac{1}{- x + c _{1}}

Solution steps

\frac{y ^{'} ( x ) + y ^{2}}{x ^{2}} = 0

Solve separable ODE:

y = - \frac{1}{- x + c _{1}}

y = - \frac{1}{- x + c _{1}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for (y^'+y^2)/(x^2)=0 ?
The solution for (y^'+y^2)/(x^2)=0 is y=-1/(-x+c_{1)}