integral from-1 to 2 of 2^x

Lösung

\int_{- 1}^{2} 2^{x} d x

\frac{7}{2 ln ( 2 )}

Dezimale

5.04943 \dots

Schritte zur Lösung

\int_{- 1}^{2} 2^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{2 ^{x}}{ln ( 2 )}]_{- 1}^{2}

Berechne die Grenzen:

\frac{7}{2 ln ( 2 )}

= \frac{7}{2 ln ( 2 )}

n = 0 \sum \infty e^{- \frac{n}{2}}

a re a x + y^{2} = 4, x + y = 2

x \to 3 - lim (x - 1)

x \to - 1 lim (6 x + 1)

\frac{\partial}{\partial x} (3 (y^{2} - x^{2}) ln (x + y))