What is the integral of ((10)/(1-sin^2(x))) ?

The integral of ((10)/(1-sin^2(x))) is 10tan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of ((10)/(1-sin^2(x)))

\int (\frac{10}{1 - sin ^{2} ( x )}) d x

10 tan (x) + C

Solution steps

\int \frac{10}{1 - sin ^{2} ( x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int \frac{1}{1 - sin ^{2} ( x )} d x

Rewrite using trig identities

= 10 \cdot \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= 10 tan (x)

Add a constant to the solution

= 10 tan (x) + C

n = 1 \sum \infty \frac{( ( - 1 ) ^{(n - 1)} )}{( n ^{3} )}

y^{^{'}} + 2 y = 3

x \to 2 - lim (2 - x)

x \to 2 - lim (\frac{1}{x - 2})

f (x) = 2 x, at x = 1

What is the integral of ((10)/(1-sin^2(x))) ?
The integral of ((10)/(1-sin^2(x))) is 10tan(x)+C