What is the solution for 3x^2y^{''}+7xy^'+y=24x+2 ?

The solution for 3x^2y^{''}+7xy^'+y=24x+2 is y=(c_{1}}{\sqrt[3]{x}}+\frac{c_{2})/x+3x+2

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3x^2y^{''}+7xy^'+y=24x+2

3 x^{2} y^{^{''}} + 7 x y^{^{'}} + y = 24 x + 2

y = \frac{c _{1}}{3 x} + \frac{c _{2}}{x} + 3 x + 2

Solution steps

3 x^{2} y^{''} (x) + 7 x y^{'} (x) + y = 24 x + 2

Solve linear ODE:

y = \frac{c _{1}}{3 x} + \frac{c _{2}}{x} + 3 x + 2

y = \frac{c _{1}}{3 x} + \frac{c _{2}}{x} + 3 x + 2

\frac{d}{d x} (\frac{x - 11}{x - 11})

\int \frac{1}{1 + 2 e ^{x} - e ^{- x}} d x

d er i v a t i v e (3 x + 5)^{7}

y^{^{'}} - \frac{y}{( 100 + 4 t )} = 150

s l o p e in t erce pt (- 2, - 5), (- 4, 4)

What is the solution for 3x^2y^{''}+7xy^'+y=24x+2 ?
The solution for 3x^2y^{''}+7xy^'+y=24x+2 is y=(c_{1}}{\sqrt[3]{x}}+\frac{c_{2})/x+3x+2