What is the integral from-infinity to 2 of e^{-x} ?

The integral from-infinity to 2 of e^{-x} is diverges

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integral from-infinity to 2 of e^{-x}

\int_{- \infty}^{2} e^{- x} d x

diverges

Solution steps

\int_{- \infty}^{2} e^{- x} d x

Compute the indefinite integral:

\int e^{- x} d x = - e^{- x} + C

Compute the boundaries:

\int_{- \infty}^{2} e^{- x} d x =

diverges

= diverges

d er i v a t i v e \frac{sin ( x )}{1 + cos ( x )}

x \to 2 lim (\frac{x}{x ^{2} - 4})

\int x sin (n x) d x

d er i v a t i v e \frac{1}{7 x ^{\frac{6}{7}}}

t a y l or 8 x e^{x}, 0

What is the integral from-infinity to 2 of e^{-x} ?
The integral from-infinity to 2 of e^{-x} is diverges