integral of 6tsin(t)

解答

\int 6 t sin (t) d t

6 (- t cos (t) + sin (t)) + C

求解步骤

\int 6 t sin (t) d t

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int t sin (t) d t

使用分布积分法

= 6 (- t cos (t) - \int - cos (t) d t)

\int - cos (t) d t = - sin (t)

= 6 (- t cos (t) - (- sin (t)))

化简

= 6 (- t cos (t) + sin (t))

解答补常数

= 6 (- t cos (t) + sin (t)) + C

a re a y = 5 x - x^{2}, x

x \to 0 lim (\frac{1}{x ^{2} - x})

d er i v a t i v e f (x) = \frac{1}{x + 6}

\int_{0}^{2 π} sin (t) d t

\frac{d}{d x} (9 lo g_{2} (x))