derivative f(v)=e^{2sin(3v)}

Lösung

ableitung von

f (v) = e^{2 s i n (3 v)}

e^{2 s i n (3 v)} \cdot 6 cos (3 v)

Schritte zur Lösung

\frac{d}{d v} (e^{2 s i n (3 v)})

Wende die Kettenregel an:

e^{2 s i n (3 v)} \frac{d}{d v} (2 sin (3 v))

= e^{2 s i n (3 v)} \frac{d}{d v} (2 sin (3 v))

\frac{d}{d v} (2 sin (3 v)) = 6 cos (3 v)

= e^{2 s i n (3 v)} \cdot 6 cos (3 v)

\int sin (x) - cos (x) d x

n = 1 \sum \infty (- 3)^{n}

\frac{d y}{d x} = \frac{x - 3}{y + 5}

n = 1 \sum \infty 3 \cdot (\frac{1}{5})^{n}

n \to \infty lim (n^{2} e^{- 3 n})