What is the derivative of f(x)= 9/(x^3) ?

The derivative of f(x)= 9/(x^3) is -(27)/(x^4)

What is the first derivative of f(x)= 9/(x^3) ?

The first derivative of f(x)= 9/(x^3) is -(27)/(x^4)

derivative of

f (x) = \frac{9}{x ^{3}}

- \frac{27}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{9}{x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 9 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 (- 3 x^{- 3 - 1})

Simplify

9 (- 3 x^{- 3 - 1}) : - \frac{27}{x ^{4}}

= - \frac{27}{x ^{4}}

\frac{d}{d x} (ln (x) - 2 x)

l a pl a ce t r an s f or m t sin (3 t) + 2 t cos (t)

t an g e n t f (x) = \frac{2 x + 1}{x + 2}, at x = 1

\frac{\partial}{\partial x} (- (5 x^{3} + 5 x y^{2}))

\frac{\partial}{\partial h} (x^{2} h)

What is the derivative of f(x)= 9/(x^3) ?
The derivative of f(x)= 9/(x^3) is -(27)/(x^4)
What is the first derivative of f(x)= 9/(x^3) ?
The first derivative of f(x)= 9/(x^3) is -(27)/(x^4)