What is the integral of sin(2x)sin(cos(2x)) ?

The integral of sin(2x)sin(cos(2x)) is 1/2 cos(cos(2x))+C

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integral of sin(2x)sin(cos(2x))

\int sin (2 x) sin (cos (2 x)) d x

\frac{1}{2} cos (cos (2 x)) + C

Solution steps

\int sin (2 x) sin (cos (2 x)) d x

Apply u-substitution

= \int sin (u) sin (cos (u)) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sin (u) sin (cos (u)) d u

Apply u-substitution

= \frac{1}{2} \cdot \int - sin (v) d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} (- \int sin (v) d v)

Use the common integral:

\int sin (v) d v = - cos (v)

= \frac{1}{2} (- (- cos (v)))

Substitute back

= \frac{1}{2} (- (- cos (cos (2 x))))

Simplify

= \frac{1}{2} cos (cos (2 x))

Add a constant to the solution

= \frac{1}{2} cos (cos (2 x)) + C

\frac{\partial}{\partial x} (sin (3 x + 4 y))

d er i v a t i v e (4 x + 7)^{2}

\frac{d}{d x} (\frac{x + 4}{x - 1})

\frac{d}{d x} (ln (5 x + 2))

d er i v a t i v e x + 12

What is the integral of sin(2x)sin(cos(2x)) ?
The integral of sin(2x)sin(cos(2x)) is 1/2 cos(cos(2x))+C