What is the limit as x approaches 0 of 1/(sin^2(2x)) ?

The limit as x approaches 0 of 1/(sin^2(2x)) is infinity

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limit as x approaches 0 of 1/(sin^2(2x))

x \to 0 lim (\frac{1}{sin ^{2} ( 2 x )})

\infty

Solution steps

x \to 0 lim (\frac{1}{sin ^{2} ( 2 x )})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (\frac{1}{sin ^{2} ( 2 x )}) = \infty

x \to 0 + lim (\frac{1}{sin ^{2} ( 2 x )}) = \infty

= \infty

What is the limit as x approaches 0 of 1/(sin^2(2x)) ?
The limit as x approaches 0 of 1/(sin^2(2x)) is infinity