taylor x^3+2x+1

Lösung

taylor

x^{3} + 2 x + 1

1 + 2 x + x^{3}

Schritte zur Lösung

Apply the Taylor Formula

= 1 + \frac{\frac{d}{d x} ( x ^{3} + 2 x + 1 ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( x ^{3} + 2 x + 1 ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x ^{3} + 2 x + 1 ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{2}{1 !} x + \frac{0}{2 !} x^{2} + \frac{6}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Fasse zusammen

= 1 + 2 x + x^{3}

d er i v a t i v e f (x) = \frac{5}{x ^{2}}

s im pl i f y \frac{x ^{2} - 1}{x}

csc (y) d x + sec^{3} (x) d y = 0

t an g e n t f (x) = x + 6, (10, 4)

\int \frac{1}{2} (1 - cos (2 x)) d x