What is the derivative of f(x)=3x^2-x+5 ?

The derivative of f(x)=3x^2-x+5 is 6x-1

What is the first derivative of f(x)=3x^2-x+5 ?

The first derivative of f(x)=3x^2-x+5 is 6x-1

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derivative of

f (x) = 3 x^{2} - x + 5

6 x - 1

Solution steps

\frac{d}{d x} (3 x^{2} - x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d x}{d x} + \frac{d}{d x} (5)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d x}{d x} = 1

\frac{d}{d x} (5) = 0

= 6 x - 1 + 0

Simplify

= 6 x - 1

x \to - 2 - lim (\frac{1 - x}{x ^{2} - 4})

n = 1 \sum \infty 3^{n} x^{n} n!

\int (x - 1)^{9} d x

s l o p e in t erce pt (- 3, 5), (- 1, - 4)

\frac{\partial}{\partial u} (\frac{1}{3} (u + v))

What is the derivative of f(x)=3x^2-x+5 ?
The derivative of f(x)=3x^2-x+5 is 6x-1
What is the first derivative of f(x)=3x^2-x+5 ?
The first derivative of f(x)=3x^2-x+5 is 6x-1