What is the derivative of (2+3x^3) ?

The derivative of (2+3x^3) is 9(2+3x)^2

What is the first derivative of (2+3x^3) ?

The first derivative of (2+3x^3) is 9(2+3x)^2

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\frac{d}{d x} ((2 + 3 x)^{3})

9 (2 + 3 x)^{2}

Solution steps

\frac{d}{d x} ((2 + 3 x)^{3})

Apply the chain rule:

3 (2 + 3 x)^{2} \frac{d}{d x} (2 + 3 x)

= 3 (2 + 3 x)^{2} \frac{d}{d x} (2 + 3 x)

\frac{d}{d x} (2 + 3 x) = 3

= 3 (2 + 3 x)^{2} \cdot 3

Simplify

= 9 (2 + 3 x)^{2}

in v erse l a pl a ce e^{t}

x \to \infty + lim (e^{- x})

\frac{\partial}{\partial x} (e^{x y^{2}} + 4 z y^{3})

(1 + x^{2}) \frac{d y}{d x} + x y = 0

d er i v a t i v e y = x^{- \frac{1}{2}}

What is the derivative of (2+3x^3) ?
The derivative of (2+3x^3) is 9(2+3x)^2
What is the first derivative of (2+3x^3) ?
The first derivative of (2+3x^3) is 9(2+3x)^2