What is the derivative of f(x)= 4/(x-2) ?

The derivative of f(x)= 4/(x-2) is -4/((x-2)^2)

What is the first derivative of f(x)= 4/(x-2) ?

The first derivative of f(x)= 4/(x-2) is -4/((x-2)^2)

derivative of

f (x) = \frac{4}{x - 2}

- \frac{4}{( x - 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4}{x - 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{1}{x - 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d x} ((x - 2)^{- 1})

Apply the chain rule:

- \frac{1}{( x - 2 ) ^{2}} \frac{d}{d x} (x - 2)

= - \frac{1}{( x - 2 ) ^{2}} \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= 4 (- \frac{1}{( x - 2 ) ^{2}} \cdot 1)

Simplify

4 (- \frac{1}{( x - 2 ) ^{2}} \cdot 1) : - \frac{4}{( x - 2 ) ^{2}}

= - \frac{4}{( x - 2 ) ^{2}}

x \to 4 - lim (e^{\frac{3}{4 - x}})

\frac{\partial}{\partial x} (x - a)

\int \frac{9 - x ^{2}}{x ^{2}} d x

\frac{\partial}{\partial x} (b lo g_{10} (x))

\frac{\partial}{\partial x} ((x_{1} + x_{2})^{2})

What is the derivative of f(x)= 4/(x-2) ?
The derivative of f(x)= 4/(x-2) is -4/((x-2)^2)
What is the first derivative of f(x)= 4/(x-2) ?
The first derivative of f(x)= 4/(x-2) is -4/((x-2)^2)