limit as x approaches 2+of (x+1)/(x-2)

解答

x \to 2 + lim (\frac{x + 1}{x - 2})

\infty

求解步骤

x \to 2 + lim (\frac{x + 1}{x - 2})

\frac{x + 1}{x - 2} = (x + 1) \frac{1}{x - 2}

= x \to 2 + lim ((x + 1) \frac{1}{x - 2})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

不定型除外

= x \to 2 + lim (x + 1) \cdot x \to 2 + lim (\frac{1}{x - 2})

x \to 2 + lim (x + 1) = 3

x \to 2 + lim (\frac{1}{x - 2}) = \infty

= 3 \cdot \infty

运用无穷大属性:

c \cdot \infty = \infty

= \infty

\int_{0}^{π} 5 sin^{2} (t co) s^{4} t d t

t an g e n t f (x) = (ln (x))^{4}, at x = 2

d er i v a t i v e y = \frac{x ^{3}}{5 - x ^{2}}

\frac{\partial}{\partial x} (ln (x^{2} + y^{4}))

a re a y = 2 x^{2} + 5 x + 6, (- 2, 0)