(\partial)/(\partial t)(1+(t-y)^2)

Lösung

\frac{\partial}{\partial t} (1 + (t - y)^{2})

2 (t - y)

Schritte zur Lösung

\frac{\partial}{\partial t} (1 + (t - y)^{2})

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial t} (1) + \frac{\partial}{\partial t} ((t - y)^{2})

\frac{\partial}{\partial t} (1) = 0

\frac{\partial}{\partial t} ((t - y)^{2}) = 2 (t - y)

= 0 + 2 (t - y)

Vereinfache

= 2 (t - y)

\int \frac{x ^{3} + 4 x ^{2} + x - 1}{x ^{3} + x ^{2}} d x

y^{^{''}} + y = 2 + x^{2}

\frac{d}{d x} (6^{4} x^{3} + x^{5} - 180 4 x^{2})

\frac{d}{d x} (\frac{- e ^{- x} x - e ^{- x}}{x ^{2}})

\int_{- 7}^{7} (1 + 49 - x^{2}) d x