What is the derivative of sqrt(x+1)-2 ?

The derivative of sqrt(x+1)-2 is 1/(2sqrt(x+1))

What is the first derivative of sqrt(x+1)-2 ?

The first derivative of sqrt(x+1)-2 is 1/(2sqrt(x+1))

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\frac{d}{d x} (x + 1 - 2)

\frac{1}{2 x + 1}

Solution steps

\frac{d}{d x} (x + 1 - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x + 1) - \frac{d}{d x} (2)

\frac{d}{d x} (x + 1) = \frac{1}{2 x + 1}

\frac{d}{d x} (2) = 0

= \frac{1}{2 x + 1} - 0

Simplify

= \frac{1}{2 x + 1}

\frac{d}{d x} (\frac{e ^{4 x^{2 + 1}}}{8})

\frac{d}{d x} (f (x) (x)^{- 1})

(x \frac{d y}{d x} + y) (2 (x + x y)) = x y

\frac{x y ^{^{'}}}{y - 2} = y^{2} - y

t an g e n t f (x) = \frac{- 6 x}{x ^{2} + 1}, (1, - 3)

What is the derivative of sqrt(x+1)-2 ?
The derivative of sqrt(x+1)-2 is 1/(2sqrt(x+1))
What is the first derivative of sqrt(x+1)-2 ?
The first derivative of sqrt(x+1)-2 is 1/(2sqrt(x+1))