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Beliebt Rechnen >

y^{''}-0.2y^'+0.01y=0,y(0)=15,y^'(0)=b

Lösung

y^{^{''}} - 0.2 y^{^{'}} + 0.01 y = 0, y (0) = 15, y^{^{'}} (0) = b

Lösung

y = 15 e^{\frac{t}{10}} + (b - \frac{3}{2}) e^{\frac{t}{10}} t

Schritte zur Lösung

y^{''} (t) - 0.2 y^{'} (t) + 0.01 y = 0

Solve linear ODE:

y = 15 e^{\frac{t}{10}} + (b - \frac{3}{2}) e^{\frac{t}{10}} t

y = 15 e^{\frac{t}{10}} + (b - \frac{3}{2}) e^{\frac{t}{10}} t

Graph

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