What is the tangent of y=x^2-5x+5,(6,11) ?

The tangent of y=x^2-5x+5,(6,11) is y=7x-31

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tangent of y=x^2-5x+5,(6,11)

tangent of

y = x^{2} - 5 x + 5, (6, 11)

y = 7 x - 31

Solution steps

Find the slope of

y = x^{2} - 5 x + 5 : \frac{d y}{d x} = 2 x - 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 7

Find the line with slope m=

7

and passing through

(6, 11) : y = 7 x - 31

y = 7 x - 31

\int_{4}^{x} 1 + 9 t d t

(- ln (1 + 6 x))^{^{'}}

x \to - 5 lim (6 x - \frac{2}{x ^{3}})

d er i v a t i v e x - 4

x \to 0 lim (\frac{1}{x} - \frac{1}{x ^{2}})

What is the tangent of y=x^2-5x+5,(6,11) ?
The tangent of y=x^2-5x+5,(6,11) is y=7x-31