What is the derivative of θcos(θ) ?

The derivative of θcos(θ) is cos(θ)-θsin(θ)

What is the first derivative of θcos(θ) ?

The first derivative of θcos(θ) is cos(θ)-θsin(θ)

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derivative of

θ cos (θ)

cos (θ) - θ sin (θ)

Solution steps

\frac{d}{d θ} (θ cos (θ))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = θ, g = cos (θ)

= \frac{d θ}{d θ} cos (θ) + \frac{d}{d θ} (cos (θ)) θ

\frac{d θ}{d θ} = 1

\frac{d}{d θ} (cos (θ)) = - sin (θ)

= 1 \cdot cos (θ) + (- sin (θ)) θ

Simplify

= cos (θ) - θ sin (θ)

\int (2 x - 4^{x}) d x

a re a y = x^{2} - 4, y = 5

\frac{d}{d x} (8^{s i n (π x)})

\int_{1}^{8} \frac{2}{x} d x

d er i v a t i v e f (x) = - 6

What is the derivative of θcos(θ) ?
The derivative of θcos(θ) is cos(θ)-θsin(θ)
What is the first derivative of θcos(θ) ?
The first derivative of θcos(θ) is cos(θ)-θsin(θ)