What is the limit as t approaches 2 of sqrt(8+t^3) ?

The limit as t approaches 2 of sqrt(8+t^3) is 4

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limit as t approaches 2 of sqrt(8+t^3)

t \to 2 lim (8 + t^{3})

4

Solution steps

t \to 2 lim (8 + t^{3})

Plug in the value

t = 2

= 8 + 2^{3}

Simplify

8 + 2^{3} : 4

= 4

a re a y = e^{- x} sin (x), y = - e^{- x} sin (x), 0 \leq x \leq π

\int \frac{cos ( 7 x )}{1 + sin ^{2} ( 7 x )} d x

\frac{d y}{d x} = \frac{y}{x ^{2} + 1}

\frac{\partial}{\partial x} (\frac{1}{x ^{2} + 1})

\frac{d}{d x} (\frac{- 2 x - y}{x + 2 y})

What is the limit as t approaches 2 of sqrt(8+t^3) ?
The limit as t approaches 2 of sqrt(8+t^3) is 4