What is the tangent of f(x)=x^2-7,\at x=2 ?

The tangent of f(x)=x^2-7,\at x=2 is y=4x-11

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tangent of f(x)=x^2-7,\at x=2

tangent of

f (x) = x^{2} - 7, at x = 2

y = 4 x - 11

Solution steps

Find the tangent point:

(2, - 3)

Find the slope of

f (x) = x^{2} - 7 : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4

Find the line with slope m=

4

and passing through

(2, - 3) : y = 4 x - 11

y = 4 x - 11

x \to 2 - lim (\frac{x ^{2}}{x ^{2} + 4})

\frac{d}{d θ} (1 + 2 sin (θ))

\frac{d}{d x} (sin (6 x^{2}))

\int - (e^{- 2 x} \cdot (5 + 2 x - 2 y^{2})) d x

4 x y^{^{'}} - 4 y = 7 x^{4}

What is the tangent of f(x)=x^2-7,\at x=2 ?
The tangent of f(x)=x^2-7,\at x=2 is y=4x-11