y^'+ycos(x)=sin(x)cos(x)

Lösung

y^{^{'}} + y \cdot cos (x) = sin (x) \cdot cos (x)

y = sin (x) - 1 + \frac{c _{1}}{e ^{s i n (x)}}

Schritte zur Lösung

y^{'} (x) + y \cdot cos (x) = sin (x) \cdot cos (x)

Solve linear ODE:

y = sin (x) - 1 + \frac{c _{1}}{e ^{s i n (x)}}

y = sin (x) - 1 + \frac{c _{1}}{e ^{s i n (x)}}

d er i v a t i v e 3 3 x^{2}

\int \frac{e ^{x} + sec ^{2} ( x )}{e ^{x} + tan ( x )} d x

in v erse l a pl a ce \frac{s - 4}{( s ^{2} + 5 ) ^{2}}

\int_{0}^{4} x x^{2} + 9 d x

\int \frac{1}{x ^{4} x ^{2} + 3} d x