xy^'-y=x^2+5x-1

Lösung

x y^{^{'}} - y = x^{2} + 5 x - 1

y = x^{2} + 5 x ln (x) + 1 + c_{1} x

Schritte zur Lösung

x y^{'} (x) - y = x^{2} + 5 x - 1

Solve linear ODE:

y = x^{2} + 5 x ln (x) + 1 + c_{1} x

y = x^{2} + 5 x ln (x) + 1 + c_{1} x

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