What is the solution for t^3(dy)/(dt)+3t^2y=7cos(t),y(pi)=0 ?

The solution for t^3(dy)/(dt)+3t^2y=7cos(t),y(pi)=0 is y=(7sin(t))/(t^3)

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t^3(dy)/(dt)+3t^2y=7cos(t),y(pi)=0

t^{3} \frac{d y}{d t} + 3 t^{2} y = 7 cos (t), y (π) = 0

y = \frac{7 sin ( t )}{t ^{3}}

Solution steps

t^{3} \frac{d y}{d t} + 3 t^{2} y = 7 cos (t)

Solve linear ODE:

y = \frac{7 sin ( t )}{t ^{3}}

y = \frac{7 sin ( t )}{t ^{3}}

x \to \infty lim (- \frac{x}{s})

d er i v a t i v e 18 (2 e^{x^{2}} x^{2} + e^{x^{2}})

l o n g d i v i s i o n \frac{x - 3}{x + 2}

\frac{d}{d x} (3^{2 x^{2}})

\frac{\partial}{\partial x} (e^{7 x^{2} + 5 y^{2}})

What is the solution for t^3(dy)/(dt)+3t^2y=7cos(t),y(pi)=0 ?
The solution for t^3(dy)/(dt)+3t^2y=7cos(t),y(pi)=0 is y=(7sin(t))/(t^3)