What is the tangent of f(x)= 9/x ,\at x=1 ?

The tangent of f(x)= 9/x ,\at x=1 is y=-9x+18

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tangent of f(x)= 9/x ,\at x=1

tangent of

f (x) = \frac{9}{x}, at x = 1

y = - 9 x + 18

Solution steps

Find the tangent point:

(1, 9)

Find the slope of

f (x) = \frac{9}{x} : \frac{df ( x )}{d x} = - \frac{9}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 9

Find the line with slope m=

- 9

and passing through

(1, 9) : y = - 9 x + 18

y = - 9 x + 18

\frac{d}{d t} (f (t) (t)^{- 1})

n = 1 \sum \infty n^{n} \cdot x^{n}

y^{^{''}} + 6 y^{^{'}} + 8 = 0

\frac{d y}{d x} = 2 x (x - 4)

\frac{d y}{d x} - \frac{y}{x} = 2 x e^{x}

What is the tangent of f(x)= 9/x ,\at x=1 ?
The tangent of f(x)= 9/x ,\at x=1 is y=-9x+18