What is (\partial)/(\partial x)(x-y-1) ?

The answer to (\partial)/(\partial x)(x-y-1) is 1

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(\partial)/(\partial x)(x-y-1)

\frac{\partial}{\partial x} (x - y - 1)

1

Solution steps

\frac{\partial}{\partial x} (x - y - 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (1) = 0

= 1 - 0 - 0

Simplify

= 1

f (x) = 5 x - 4

d er i v a t i v e y = x + 3 x

\frac{d}{d x} (e^{x y} ln (z))

d er i v a t i v e p (x) = x - 1 - 3 x^{2}

\int 3 e^{s i n (x)} cos (x) d x

What is (\partial)/(\partial x)(x-y-1) ?
The answer to (\partial)/(\partial x)(x-y-1) is 1