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Frequently Asked Questions (FAQ)
What is the tangent of f(x)=(x^3)/3+2x^2+13x-5 ?
- The tangent of f(x)=(x^3)/3+2x^2+13x-5 is y=(a_{0}^2+4a_{0}+13)x-a_{0}^3-2a_{0}^2+(a_{0}^3)/3-5