What is the integral of x(x-21)^2 ?

The integral of x(x-21)^2 is (x^4)/4-14x^3+(441x^2)/2+C

integral of x(x-21)^2

\int x (x - 21)^{2} d x

\frac{x ^{4}}{4} - 14 x^{3} + \frac{441 x ^{2}}{2} + C

Solution steps

\int x (x - 21)^{2} d x

Expand

x (x - 21)^{2} : x^{3} - 42 x^{2} + 441 x

= \int x^{3} - 42 x^{2} + 441 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x - \int 42 x^{2} d x + \int 441 x d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int 42 x^{2} d x = 14 x^{3}

\int 441 x d x = \frac{441 x ^{2}}{2}

= \frac{x ^{4}}{4} - 14 x^{3} + \frac{441 x ^{2}}{2}

Add a constant to the solution

= \frac{x ^{4}}{4} - 14 x^{3} + \frac{441 x ^{2}}{2} + C

\int 3 sec (x) tan (x) d x

d er i v a t i v e y = 2 x + 4

d er i v a t i v e \frac{48}{x}

\frac{d}{d x} (1 + 2 x^{\frac{3}{2}})

\int \frac{x ^{2}}{2 x + 1} d x

What is the integral of x(x-21)^2 ?
The integral of x(x-21)^2 is (x^4)/4-14x^3+(441x^2)/2+C