integral of in(x)

解答

\int in (x) d x

\frac{in x ^{2}}{2} + C

求解步骤

\int in x d x

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= in \cdot \int x d x

使用幂法则

= in \frac{x ^{2}}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{in x ^{2}}{2}

解答补常数

= \frac{in x ^{2}}{2} + C

n = 1 \sum \infty \frac{1}{( 2 n - 1 ) ^{5}}

\frac{d}{d x} (4 x^{5} - 5 x^{4})

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t an g e n t f (x) = \frac{x ^{2} - 1}{x ^{2} + 1}, at x = 0

\frac{\partial}{\partial x} (- 4 cos (2 x))